Thun/docs/Compiling_Joy.ipynb

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from notebook_preamble import D, J, V, define

Compiling Joy

Given a Joy program like:

sqr == dup mul

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V('23 sqr')

      . 23 sqr
   23 . sqr
   23 . dup mul
23 23 . mul
  529 . 

How would we go about compiling this code (to Python for now)?

Naive Call Chaining

The simplest thing would be to compose the functions from the library:

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dup, mul = D['dup'], D['mul']

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def sqr(stack, expression, dictionary):
    return mul(*dup(stack, expression, dictionary))

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old_sqr = D['sqr']
D['sqr'] = sqr

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V('23 sqr')

    . 23 sqr
 23 . sqr
529 . 

It's simple to write a function to emit this kind of crude "compiled" code.

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def compile_joy(name, expression):
    term, expression = expression
    code = term +'(stack, expression, dictionary)'
    format_ = '%s(*%s)'
    while expression:
        term, expression = expression
        code = format_ % (term, code)
    return '''\
def %s(stack, expression, dictionary):
    return %s
''' % (name, code)


def compile_joy_definition(defi):
    return compile_joy(defi.name, defi.body)

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print compile_joy_definition(old_sqr)

def sqr(stack, expression, dictionary):
    return mul(*dup(stack, expression, dictionary))

But what about literals?

quoted == [unit] dip

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unit, dip = D['unit'], D['dip']

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# print compile_joy_definition(D['quoted'])
# raises
# TypeError: can only concatenate tuple (not "str") to tuple

For a program like foo == bar baz 23 99 baq lerp barp we would want something like:

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def foo(stack, expression, dictionary):
    stack, expression, dictionary = baz(*bar(stack, expression, dictionary))
    return barp(*lerp(*baq((99, (23, stack)), expression, dictionary)))

You have to have a little discontinuity when going from a symbol to a literal, because you have to pick out the stack from the arguments to push the literal(s) onto it before you continue chaining function calls.

Compiling Yin Functions

Call-chaining results in code that does too much work. For functions that operate on stacks and only rearrange values, what I like to call "Yin Functions", we can do better.

We can infer the stack effects of these functions (or "expressions" or "programs") automatically, and the stack effects completely define the semantics of the functions, so we can directly write out a two-line Python function for them. This is already implemented in the joy.utils.types.compile_() function.

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from joy.utils.types import compile_, doc_from_stack_effect, infer_string
from joy.library import SimpleFunctionWrapper

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stack_effects = infer_string('tuck over dup')

Yin functions have only a single stack effect, they do not branch or loop.

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for fi, fo in stack_effects:
    print doc_from_stack_effect(fi, fo)

(a2 a1 -- a1 a2 a1 a2 a2)

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source = compile_('foo', stack_effects[0])

All Yin functions can be described in Python as a tuple-unpacking (or "-destructuring") of the stack datastructure followed by building up the new stack structure.

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print source

def foo(stack):
  """
  ::

  (a2 a1 -- a1 a2 a1 a2 a2)

  """
  (a1, (a2, s1)) = stack
  return (a2, (a2, (a1, (a2, (a1, s1)))))

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exec compile(source, '__main__', 'single')

D['foo'] = SimpleFunctionWrapper(foo)

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V('23 18 foo')

               . 23 18 foo
            23 . 18 foo
         23 18 . foo
18 23 18 23 23 . 

Compiling from Stack Effects

There are times when you're deriving a Joy program when you have a stack effect for a Yin function and you need to define it. For example, in the Ordered Binary Trees notebook there is a point where we must derive a function Ee:

   [key old_value left right] new_value key [Tree-add] Ee
------------------------------------------------------------
   [key new_value left right]

While it is not hard to come up with this function manually, there is no necessity. This function can be defined (in Python) directly from its stack effect:

   [a b c d] e a [f] Ee
--------------------------
   [a e c d]

(I haven't yet implemented a simple interface for this yet. What follow is an exploration of how to do it.)

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from joy.parser import text_to_expression

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Ein = '[a b c d] e a [f]'  # The terms should be reversed here but I don't realize that until later.
Eout = '[a e c d]'
E = '[%s] [%s]' % (Ein, Eout)

print E

[[a b c d] e a [f]] [[a e c d]]

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(fi, (fo, _)) = text_to_expression(E)

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fi, fo

Out [22]:

(((a, (b, (c, (d, ())))), (e, (a, ((f, ()), ())))),
 ((a, (e, (c, (d, ())))), ()))

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Ein = '[a1 a2 a3 a4] a5 a6 a7'
Eout = '[a1 a5 a3 a4]'
E = '[%s] [%s]' % (Ein, Eout)

print E

[[a1 a2 a3 a4] a5 a6 a7] [[a1 a5 a3 a4]]

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(fi, (fo, _)) = text_to_expression(E)

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fi, fo

Out [25]:

(((a1, (a2, (a3, (a4, ())))), (a5, (a6, (a7, ())))),
 ((a1, (a5, (a3, (a4, ())))), ()))

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def type_vars():
    from joy.library import a1, a2, a3, a4, a5, a6, a7, s0, s1
    return locals()

tv = type_vars()
tv

Out [26]:

{'a1': a1,
 'a2': a2,
 'a3': a3,
 'a4': a4,
 'a5': a5,
 'a6': a6,
 'a7': a7,
 's0': s0,
 's1': s1}

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from joy.utils.types import reify

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stack_effect = reify(tv, (fi, fo))
print doc_from_stack_effect(*stack_effect)

(... a7 a6 a5 [a1 a2 a3 a4 ] -- ... [a1 a5 a3 a4 ])

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print stack_effect

(((a1, (a2, (a3, (a4, ())))), (a5, (a6, (a7, ())))), ((a1, (a5, (a3, (a4, ())))), ()))

Almost, but what we really want is something like this:

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stack_effect = eval('(((a1, (a2, (a3, (a4, s1)))), (a5, (a6, (a7, s0)))), ((a1, (a5, (a3, (a4, s1)))), s0))', tv)

Note the change of () to JoyStackType type variables.

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print doc_from_stack_effect(*stack_effect)

(a7 a6 a5 [a1 a2 a3 a4 ...1] -- [a1 a5 a3 a4 ...1])

Now we can omit a3 and a4 if we like:

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stack_effect = eval('(((a1, (a2, s1)), (a5, (a6, (a7, s0)))), ((a1, (a5, s1)), s0))', tv)

The right and left parts of the ordered binary tree node are subsumed in the tail of the node's stack/list.

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print doc_from_stack_effect(*stack_effect)

(a7 a6 a5 [a1 a2 ...1] -- [a1 a5 ...1])

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source = compile_('Ee', stack_effect)
print source

def Ee(stack):
  """
  ::

  (a7 a6 a5 [a1 a2 ...1] -- [a1 a5 ...1])

  """
  ((a1, (a2, s1)), (a5, (a6, (a7, s0)))) = stack
  return ((a1, (a5, s1)), s0)

Oops! The input stack is backwards...

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stack_effect = eval('((a7, (a6, (a5, ((a1, (a2, s1)), s0)))), ((a1, (a5, s1)), s0))', tv)

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print doc_from_stack_effect(*stack_effect)

([a1 a2 ...1] a5 a6 a7 -- [a1 a5 ...1])

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source = compile_('Ee', stack_effect)
print source

def Ee(stack):
  """
  ::

  ([a1 a2 ...1] a5 a6 a7 -- [a1 a5 ...1])

  """
  (a7, (a6, (a5, ((a1, (a2, s1)), s0)))) = stack
  return ((a1, (a5, s1)), s0)

Compare:

   [key old_value left right] new_value key [Tree-add] Ee
------------------------------------------------------------
   [key new_value left right]

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eval(compile(source, '__main__', 'single'))
D['Ee'] = SimpleFunctionWrapper(Ee)

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V('[a b c d] 1 2 [f] Ee')

                  . [a b c d] 1 2 [f] Ee
        [a b c d] . 1 2 [f] Ee
      [a b c d] 1 . 2 [f] Ee
    [a b c d] 1 2 . [f] Ee
[a b c d] 1 2 [f] . Ee
        [a 1 c d] . 

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Working with Yang Functions

Consider the compiled code of dup:

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def dup(stack):
    (a1, s23) = stack
    return (a1, (a1, s23))

To compile sqr == dup mul we can compute the stack effect:

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stack_effects = infer_string('dup mul')
for fi, fo in stack_effects:
    print doc_from_stack_effect(fi, fo)

(n1 -- n2)

Then we would want something like this:

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def sqr(stack):
    (n1, s23) = stack
    n2 = mul(n1, n1)
    return (n2, s23)

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How about...

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stack_effects = infer_string('mul mul sub')
for fi, fo in stack_effects:
    print doc_from_stack_effect(fi, fo)

(n4 n3 n2 n1 -- n5)

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def foo(stack):
    (n1, (n2, (n3, (n4, s23)))) = stack
    n5 = mul(n1, n2)
    n6 = mul(n5, n3)
    n7 = sub(n6, n4)
    return (n7, s23)


# or

def foo(stack):
    (n1, (n2, (n3, (n4, s23)))) = stack
    n5 = sub(mul(mul(n1, n2), n3), n4)
    return (n5, s23)

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stack_effects = infer_string('tuck')
for fi, fo in stack_effects:
    print doc_from_stack_effect(fi, fo)

(a2 a1 -- a1 a2 a1)

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Compiling Yin~Yang Functions

First, we need a source of Python identifiers. I'm going to reuse Symbol class for this.

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from joy.parser import Symbol

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def _names():
    n = 0
    while True:
        yield Symbol('a' + str(n))
        n += 1

names = _names().next

Now we need an object that represents a Yang function that accepts two args and return one result (we'll implement other kinds a little later.)

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class Foo(object):

    def __init__(self, name):
        self.name = name

    def __call__(self, stack, expression, code):
        in1, (in0, stack) = stack
        out = names()
        code.append(('call', out, self.name, (in0, in1)))
        return (out, stack), expression, code

A crude "interpreter" that translates expressions of args and Yin and Yang functions into a kind of simple dataflow graph.

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def I(stack, expression, code):
    while expression:
        term, expression = expression
        if callable(term):
            stack, expression, _ = term(stack, expression, code)
        else:
            stack = term, stack
            code.append(('pop', term))

    s = []
    while stack:
        term, stack = stack
        s.insert(0, term)
    if s:
        code.append(('push',) + tuple(s))
    return code

Something to convert the graph into Python code.

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strtup = lambda a, b: '(%s, %s)' % (b, a)
strstk = lambda rest: reduce(strtup, rest, 'stack')


def code_gen(code):
    coalesce_pops(code)
    lines = []
    for t in code:
        tag, rest = t[0], t[1:]

        if tag == 'pop':
            lines.append(strstk(rest) + ' = stack')

        elif tag == 'push':
            lines.append('stack = ' + strstk(rest))

        elif tag == 'call':
            #out, name, in_ = rest
            lines.append('%s = %s%s' % rest)

        else:
            raise ValueError(tag)

    return '\n'.join('    ' + line for line in lines)


def coalesce_pops(code):
    index = [i for i, t in enumerate(code) if t[0] == 'pop']
    for start, end in yield_groups(index):
        code[start:end] = \
            [tuple(['pop'] + [t for _, t in code[start:end][::-1]])]


def yield_groups(index):
    '''
    Yield slice indices for each group of contiguous ints in the
    index list.
    '''
    k = 0
    for i, (a, b) in enumerate(zip(index, index[1:])):
        if b - a > 1:
            if k != i:
                yield index[k], index[i] + 1
            k = i + 1
    if k < len(index):
        yield index[k], index[-1] + 1


def compile_yinyang(name, expression):
    return '''\
def %s(stack):
%s
    return stack
''' % (name, code_gen(I((), expression, [])))

A few functions to try it with...

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mul = Foo('mul')
sub = Foo('sub')

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def import_yin():
    from joy.utils.generated_library import *
    return locals()

yin_dict = {name: SimpleFunctionWrapper(func) for name, func in import_yin().iteritems()}

yin_dict

dup = yin_dict['dup']

#def dup(stack, expression, code):
#    n, stack = stack
#    return (n, (n, stack)), expression

<ipython-input-74-a6ea700b09d9>:1: SyntaxWarning: import * only allowed at module level
  def import_yin():

... and there we are.

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print compile_yinyang('mul_', (names(), (names(), (mul, ()))))

def mul_(stack):
    (a31, (a32, stack)) = stack
    a33 = mul(a32, a31)
    stack = (a33, stack)
    return stack

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e = (names(), (dup, (mul, ())))
print compile_yinyang('sqr', e)

def sqr(stack):
    (a34, stack) = stack
    a35 = mul(a34, a34)
    stack = (a35, stack)
    return stack

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e = (names(), (dup, (names(), (sub, (mul, ())))))
print compile_yinyang('foo', e)

def foo(stack):
    (a36, (a37, stack)) = stack
    a38 = sub(a37, a36)
    a39 = mul(a38, a36)
    stack = (a39, stack)
    return stack

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e = (names(), (names(), (mul, (dup, (sub, (dup, ()))))))
print compile_yinyang('bar', e)

def bar(stack):
    (a40, (a41, stack)) = stack
    a42 = mul(a41, a40)
    a43 = sub(a42, a42)
    stack = (a43, (a43, stack))
    return stack

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e = (names(), (dup, (dup, (mul, (dup, (mul, (mul, ())))))))
print compile_yinyang('to_the_fifth_power', e)

def to_the_fifth_power(stack):
    (a44, stack) = stack
    a45 = mul(a44, a44)
    a46 = mul(a45, a45)
    a47 = mul(a46, a44)
    stack = (a47, stack)
    return stack

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